friends help: After a recent tramatic injury, I was diaagnosed with two mini - Help.com

After a recent tramatic injury, I was diaagnosed with

two mini strokes, leaving me with number dislexia, and some memory loss, like short term does not work well every day.
I am repeating myself on here but I need to get this story out b4, I ask for assitance.
I am completing my degree in health and human services, not math related, thank the Goddess, and I have one last course to fullfill b4 I receive my degree. Algebra. I only have a few questions left I need assistance with, but I really need someone who knows their stuff. I am not going to remember most of it, I probably will not learn from what I get assistance on, and I will deffinatly never use it in my field of work. So that out of the way. I do not want to mislead others, and sorry if I have done so before now.
If anyone out there enjoys math, or enjoys assisting others with math, especially algebra, and does not mind showing work, you are my newest best friend.
hit me back, and I will post the questions as I receive them, most are not exactly the same, as I am not looking to cheat, just a translation of what is there, so I can then figure out how to complete the problems I do have. Thank you ahead of time. Got a question, shout it out to me, Im all ears..cute little ears, but ears, none the less, lol

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Since writing this post gypsie may have helped people, but has not within the last 4 days. gypsie is a verified member, has been around for 5 years, 8 months and has 2 posts and 88 replies to their name.

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Anonymous #
5 years, 8 months ago (4 minutes after post)

good luck 2 u. i’d help, but i’ve sucked at math for yrs.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 8 months ago (16 minutes after post)

:)

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ScreaminglyWonderful invited 1 user to read this post 5 years, 8 months ago.

Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 8 months ago (1 hour, 38 minutes after post)

As long as you’re trying, I’m willing to help.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 8 months ago (12 hours, 20 minutes after post)

These are online courses, no labs. I only have a few questions left now.. I,m nearing the end of a very long 10 (email removed) Good advice for someone physically on campus though..thanx annonymous

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (18 hours, 3 minutes after post)

Thank you Creal.
I only have this last final to complete. about 30 or less questions. The ada are involved, but unfortunatly I still have to pass this course so I do not have to repay my student loans immediatly, and I only have a small time window available to complete it, as my bachelors begins immediatly afterwards. NOTHING MATH RELATED, SCHOOL WISE EVER AGAIN..YA..

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (18 hours, 3 minutes after post)

therapsis, thank you for the sight, I shall check it out, blessed be..

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (18 hours, 9 minutes after post)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (18 hours, 11 minutes after post)

Solve. 7x + 7 = 6x
all for today..any takers, thank you

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (18 hours, 34 minutes after post)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

Le’ts have ’s’ be the two equal sides of the triangle and ‘b’ be the base. We can derive two equations from what’s given:

Perimeter:
2*s + b = 29
4*b - 8 = s

Now that we have two functions we can use elimination or substiution to solve for s.
I’m going to use substitution (since ’s’ is already solved for). I’m going to plug in the equation (4*b - 8) as ’s’ in the first equation:
2*s + b = 29
2*(4*b - 8) + b = 29
8*b - 16 + b = 29
9*b - 16 = 29
9*b = 45
b = 5

So the base side is 5, let’s plug this back into one of the original equations to find ’s.’ I’m using the secod one:
4*b - 8 = s
4*(5) - 8 = s
20 - 8 = s
12 = s

So the two equal sides are 12 centimers long.
————–

7x + 7 = 6x
Well, we can just manipulate both sides of the equation to find x. Let’s try to get x by itself on one side of the equation. We can start by subtracting ‘6x’ from both sides:
x + 7 = 0
Then we can subtract seven from both sides to get:
x = (-7)

So you’re answer is x = (-7)

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gapeach201 offline Verified User (5 years, 8 months) Long Term User Shouts: 5 #
Atlanta, GA, US | 5 years, 7 months ago (18 hours, 35 minutes after post)

aw im sry

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Help me with: i need help!
gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (19 hours, 21 minutes after post)

I only have a little over 2 wks to complete this and get final grade, but a tutor for someone able to get out of the house would benefit, but thank you!
I am taking online courses, and by the time I got someone to drive to the local university, they may be able to find someone else who has the time to assist me, but by then, Id be out of time. Maybe if anyone else took this course, though I would recomend it not be online. Regardless of mental and physical limitations. See, I was in the class, when the two mini stroke hit, I was already enrolled, I had to pass or fail. Im not about to fail..I cannot go to another college now. I would lose all my schlorship funds, and my loans would have to be regenerated, Good advice for those not in my situation, however.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (19 hours, 26 minutes after post)

ok, here is another..

The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle.2l*2w
———————————————————————
Solve. 6x + 4(3x – 2) = 6x + 2
Pre thanks again..
.. a word problem, 0/-5 =-5, but is that considered undefined? In algebra, I mean?

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 2 hours after post)

helps tremendously. I honestly feel, all the ones I did not understand are on the final..hahaha, blah, oh well, I am working on them all day, until I complete all of them, thank you so very much.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 15 hours after post)

This is great theer were a couple more like that last one and I figured them out by myself, thank you!
——————————————————
Here are a coupe more I am still finding difficult.
Solve the system by graphing.
3x – y = 1
3x – y = 2
———————————
Rewrite the equation –8x – 5y = –45 as a function of x.

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gapeach201 offline Verified User (5 years, 8 months) Long Term User Shouts: 5 #
Atlanta, GA, US | 5 years, 7 months ago (1 day, 17 hours after post)

honestly dude u need a tutor!!

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Help me with: i need help!
gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 17 hours after post)

3x-y=1
3x+1=y
3x=1y
x=4y. I think, but I second guess myself so much, and I think that I also get finding x confused with the 3x. I see the x and think that it is the same, half way through I either forgot what(x or y) I was trying to find, or forgot what I was trying to ignore.. Then all the different rules..This is frustrating. I cannot even begin to explain how frustrating it has been..
But I appreciate all the assistnace I have received..
I also went to the graph site. In our text there is one similar but we cannot use the graphs with squares..go figure, algebra, no squares..
alot has changed since I was in highschool 100 yrs ago

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 18 hours after post)

hey Georgia peach..I loved ATL whenever I would visit, twice or more a year. I just moved from the south back up north..in time for a great winter..burrrr, yuck! Yes I need a tutor, but I only have a few more, and no time to find a tutor right now. But thanx sweetheart..and I dont mean that in a pedifile sort of way.. Gotta watch what I say on these sites, I forget we are all not actually in a college based environment with everyone of legal age.

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gapeach201 offline Verified User (5 years, 8 months) Long Term User Shouts: 5 #
Atlanta, GA, US | 5 years, 7 months ago (1 day, 18 hours after post)

its cool..it dont bother me!!! lol!! so u liked it in ATL?

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 18 hours after post)

ya, ATL is hot. My cousin resides at the base of Stone Mountain. She adores it! Lively place, nice people, and very arts and theater based. I loved all the little coffee shops, and small niche stores. We went to stone mountain and I love history, so I had a great time.I also love to shop the underground, it fascinates me every time I go there. Ive been to the coke muesum, and that was different..I was in ATl when the Olympics were there inwas it 97, 96, 98>? I cannot really remember the dates, but I have a vivid memory of colors sounds, and places.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 18 hours after post)

a funtion of x would mean it would go right after a number, correct?
I came up with f(x)-8x-5y=-45

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gapeach201 offline Verified User (5 years, 8 months) Long Term User Shouts: 5 #
Atlanta, GA, US | 5 years, 7 months ago (1 day, 18 hours after post)

yea me 2!! i go underground all the time!!! i go watch the base ball games!! its really fun

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gapeach201 offline Verified User (5 years, 8 months) Long Term User Shouts: 5 #
Atlanta, GA, US | 5 years, 7 months ago (1 day, 18 hours after post)

not my problem we talkin!!

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gapeach201 offline Verified User (5 years, 8 months) Long Term User Shouts: 5 #
Atlanta, GA, US | 5 years, 7 months ago (1 day, 18 hours after post)

ok

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 19 hours after post)

We can talk later, annoymous is right, this is a math help. I really need the assistance. Please do not unsubscribe.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 20 hours after post)

I do not need to solve it, I need to rewrite it as a function of x, or
f(x)=-8x-5y=-45 I think I am supposed to rewrite it like that. If I tried to solve it I would put something like -8x=-40 subtract the 5 from the left and add it to the right, x=-48 subtract the -8 from left and add it to the right. Am I close?

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (1 day, 20 hours after post)

ok about the 3x-y problem, I saw it backwards, and then added wrong. so it should look like
3x – y = 1
3x+1=y
3x=y
x=3y

3x – y = 2
3x+2=y
3x=y
x=3y
I then need to graph these points(3,1)(3,2) I think those would be the points if I did the problem correctly.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (2 days, 1 hour after post)

I have contacted my instructor, several times. My collaga has worked with me the best they can under my circumstances, My neuro syrgyn thinks I over did it by continuing, but if I do not complete this course, now, I lose all future funding, and my loans will have to be repaid immediatly. With the medical I have now, I cannot afford the loan repay right now. Im in a catch 22. Thnks for your assistance, If you cannot help me, I understand.
Please understand as well, I am limited on how much more time I am allowed.
I have short term ememory loss and number dislexia from the strokes, I am not completly able to retain the information, I get half way through the operations , and forget what I was trying to do. It takes me three times as long to graps the idea, and then to actually complete the problems then an less then average student. however I am required to complete and pass this course. catch 22.. I did not wish any of this onme, or anyone else. I want to get through this, and get on with my life. What I have left of it. It is easy for you to get frustrated repeating what you have said, but I look back over the work, and it’s like starting over with me, if I skip even one day. Ive been at this straight for over nine weeks now. Im frazzeled, fried, and burnt out. Please remember, I only ask for assistance, because I cannot retain the numbers. I would not seek nearly as much assistance had I not had these two strokes.
I was holding a very high gpa, and not a worry in the world, b4 the chiropractor took it all away.Im sure you hear this kind of thing everyday, and get frustrated because you are so very intelligent with mathmatical operations, and some of us are not, and most never will be/ I am pleased for you,and know one day you will use your talent to assist others, and wish you well with your endeavours.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (2 days, 1 hour after post)

Anyone ELSE out there, willing to help a strugling student? I only have a few more questions, and ILL leave everyone alone.

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (2 days, 2 hours after post)

Ok, I’m a little lost in what problem you’re working on.

Solve the system by graphing.
3x – y = 1
3x – y = 2

Well, you’ll find out when you graph this that these lines are parallel. Therefore this is an inconsistant system. If you look at the equation, you may notice that the equations have the same slope but have different y-interesepts.
———————————
Rewrite the equation –8x – 5y = –45 as a function of x.

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (2 days, 2 hours after post)

oops…. I didn’t mean to send that last one yet…

Rewrite the equation –8x – 5y = –45 as a function of x.

What this is asking is to have everyting set equal to x. So you want to get x by itself on one side of the equation:

–8x – 5y = –45
Let’s start by adding 5y to both sides:
-8x = -45 + 5y
Then we can divide both sides by (-8):
x = (45/8) - ((5y)/8)
So that should be your answer. Nasty fractions but:
x = (45/8) - ((5y)/8)

Good luck!

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (4 days, 14 hours after post)

Solve the system by substitution method.
1 x – y = –3
x – y = 4
still not too sure on these.
—————————
2 Given f(x) = 3x + 3, find f(a + 1).
————————————
3 Are the following lines parallel, perpendicular, or neither?
L1 with equation x – 2y = 10
L2 with equation 2x + y = 2
I got perpindicula, but want a check, thank you
————————————–
4 Solve. 4(x + 2) – 3x = x – 6,
this one is tricky cause it ciuld have an answermof no answer, but- just beacuse I cannot find the answer, doesnt mean that is the answer. I hate these kind. Never sure if Im right or wrong..lingering doubt..got enough of tht already..lol..

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (4 days, 16 hours after post)

x – y = –3
x – y = 4

Well, just by looking at this, I can tell you that this is an inconsistant system. The lines have the slope, but different y-intersepts. This implies that the two lines are parallel and will never intersect.
————-
Given f(x) = 3x + 3, find f(a + 1).

For this, all you have to do is subsitute “a + 1″ as x:
3x + 3
3(a + 1) + 3
3a + 3 + 3
3a + 6
————-
L1 with equation x – 2y = 10
L2 with equation 2x + y = 2

Yes, these lines are perpendicular. You can take the slope of each line by solving for y. I’ll start with the first line and then I’ll do the second:

x – 2y = 10
Add 2y to both sides:
x = 10 + 2y
Subtract 10 from both side
x - 10 = 2y
Divide both sides by 2:
(1/2)*x - 5 = y
So according to the formula y = m*x + b where ‘m’ is slope and ‘b’ is the y-interesept, the slope for the first line is (1/2).

2x + y = 2
Subtract 2x from both sides:
y = -2x + 2
According to the formula y = m*x + b where ‘m’ is slope and ‘b’ is the y-interesept, the slope for the first line is (-2).

So the two slope are (1/2) and -2, which are negative inverses of each other, indicating perpendicular lines.
———–
4(x + 2) – 3x = x – 6

Let’s distribute the 4x out first by multiplying the polynomial:
4x + 8 - 3x = x - 6
x + 8 = x - 6
We can add 6 to both sides:
x + 14 = x
All that’s left is to subtract x from both sides, which will leave us with 14 = 0, which is a false statement. So this equation has no solution and the equation will never be true for any value of x.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 1 hour after post)

Thank you so very much. I have a couple more, and I used what you provided me ,and worked them out. If I do them immediatly after one anothereem to get them if I move on, but once I stop, or read something else, or the problems are scattered from chapter to another and back agian, Im a goner..I really appreciate your assistance.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 1 hour after post)

Write the equation of the line that passes through point (6, 4) with a slope of 2.
————————————————————————– ——–
Use the indicated property to write an expression that is equivalent to the following expression.
20 • 16 + 20 • 12 (distributive property)
————————————————————–
An employee who produces x units per hour earns an hourly wage of y = 0.55x + 8 (in dollars). Find the hourly wage for an employee who produces 9 units per hour.
————————————————————————- -
Solve. 10x –1/4 = 9x + 3/8

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (5 days, 1 hour after post)

Write the equation of the line that passes through point (6, 4) with a slope of 2

Well, we can use the equation: y = m*x + b. Where ‘m’ is slope, and ‘b’ is the y-intersept. So let’s subsitute 2 for ‘m’ since it’s given:
y = (2)*x + b

Now we’re given a coordinate the line passes through. If we plug in x and y from there, we can find ‘b’:
y = (2)*x + b
4 = (2)*6 + b
4 = 12 + b
-8 = b
So the y-intersept will have to be -8. From this we can form the equation for the line:
y = (2)*x - 8
——————-
Use the indicated property to write an expression that is equivalent to the following expression.
20 • 16 + 20 • 12 (distributive property)

Well, I’m really not sure what the question is looking for. Both have a 20, and I would assume the answer would look like this:
20*(16 + 12) (I think this is the answer)

However, you can factor an additional 4 from the polynomial:
80*(4 + 3)
And when you solve this you’ll get 560. I think either of those two equations would work, but I’d go with the first one I wrote.
————-
An employee who produces x units per hour earns an hourly wage of y = 0.55x + 8 (in dollars). Find the hourly wage for an employee who produces 9 units per hour.

Ok, take the equation “y = 0.55x + 8″ and subsitute 9 in for x:
y = 0.55x + 8
y = 0.55*(9) + 8
y = 4.95 + 8
y = 12.95

So this worker earns $12.95 an hour
————-
Solve. 10x –1/4 = 9x + 3/8

Ok, I’m going to assume you meant the following:
10x – (1/4) = 9x + (3/8)
Now we have to get x by itself.
We can start this by subtracting 9x from both sides:
x - (1/4) = (3/8)
Then we can add (1/4) to both sides to get:
x = (5/8)

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 1 hour after post)

what do I do with the 10x though?, and the problem does not have ( around the numbers) it states exactly solve 10x-1/4=9x=3/8. I started to do the same as you showed me, but then I still have a 10x left over in the equation..do I leave it out, or could the answer beone involved with ading 10x to the side on the right, ..does this question make any sense?

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 1 hour after post)

Solve. –9x + 5 + 7x = –2x + 5
This one is way too long, I tried this
-9xsquared=-2x-7
-9xsquared=-9
xsquared=x, am I heading the right way here?

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (5 days, 1 hour after post)

it states exactly solve 10x-1/4=9x=3/8
Looks a little different tha what I answered a second ago :P
I’ll assume you meant that to a “+” instead of an “=”

Here I’ll try explain my first step a little better:
10x - (1/4) = 9x + (3/8)
My first step was to subtract “9x” from both sids:
10x - 9x - (1/4) = 9x - 9x + (3/8)
So on the left side, 10x - 9x will leave just x. On the right, the 9x will cancel with the - 9x.
————–
Solve. –9x + 5 + 7x = –2x + 5

Well, this is going to be one of those screwy answers anyway. On the left, if you add 7x to -9x, it will equal -2x. So we can simplyfy the left side:
-9x + 7x + 5
-2x + 5

Which happens to equal the right side of the equation:
-2x + 5 = -2x + 5
So, this equation is true for all values of x.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 2 hours after post)

so my choices for this answer are identity, no solution, zero or one, I think it would be identity in this case, correct>?

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 2 hours after post)

Which of the ordered pairs is a solution for the equation 3x – 4y = 12?
(0, 3)
(–4, 0)
(–4, –3)
(0, –3)
———————————-
Write the equation of the line that passes through point (0, –9) with a slope of –3.
———————————————-

I may only have one or two more to confirm, thank you again.

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (5 days, 2 hours after post)

I’m pretty sure it’s identity.

Which of the ordered pairs is a solution for the equation 3x – 4y = 12?
(0, 3)
(–4, 0)
(–4, –3)
(0, –3)

Alright, let’s take the coordinates and plug it into the equation:
(0, 3)
3x – 4y = 12
3*(0) - 4*(3) = 12
0 - 12 = 12
-12 = 12
This one is not a solution.

(-4, 0)
3x – 4y = 12
3*(-4) - 4*(0) = 12
-12 - 0 = 12
-12 = 12
This one is not a solution

(-4, -3)
3x – 4y = 12
3*(-4) - 4*(-3) = 12
-12 - (-12) = 12
0 = 12
This one is not a solution

(0,-3)
3x – 4y = 12
3*(0) - 4*(-3) = 12
0 - (-12) = 12
12 = 12
This one IS a solution

So the only coordinate that is a solution for 3x – 4y = 12 is (0,-3).
———
Write the equation of the line that passes through point (0, –9) with a slope of –3.

Well, the coordinate given is at x=0, showing the y-intersept to be -9, so we don’t have to solve for it. The slope of the equation is -3. So with the formula y = m*x + b, we get the equation:

y = -3*x - 9

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 2 hours after post)

You are awsome, and I knew the last one, I got it, before I checked, thanks anyway..
————————————————————————– ————
-Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.
I dont even remember seeing this one anywhere let alone I could not find an example in my book..Maybe it is a trick question..no..Im sure you’ve already figured it out..:)

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 2 hours after post)

Enrique puts 12% of his monthly paycheck in an IRA. If he invests $72 in his IRA, how much was his paycheck? .12×72,x$8.64=$622.08
Did I do this one correctly?

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (5 days, 3 hours after post)

Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.

We can make a system of equations with what’s given. Let’s make the two integers be ‘x’ (the first) and ‘y’ (the second).

x + 1 = y (Two consecutive integers)
2*x + 7*y = 88

We can use either elimination or subsitution to solve for the system. I’m going to use subsitution since the first equation is already solve for y. So I’ll plug in “x + 1″ as y in the second equation:

2*x + 7*(x + 1) = 88
2*x + 7*x + 7 = 88
9*x + 7 = 88
Subtract 7 from both sides:
9*x = 81
Divide both sides by 9:
x = 9

So the first integer is 9. If we plug this back into one of our equations, we can solve for y. I’m going to use the first one:

x + 1 = y
9 + 1 = y
10 = y

So, the two consecutive integers are 9 and 10.
————
Enrique puts 12% of his monthly paycheck in an IRA. If he invests $72 in his IRA, how much was his paycheck?

.12*x = 72
So divide both sides by .12
x = 600

I got his paycheck to be $600

I’m not sure where you got $622.08 from, but there might be some tax or special finacial property I don’t see in the problem.

The way I see it: he put $72 in an account, which is supposed to be 12 percent of his paycheck. After my algebra, his paycheck came out to be $600. If you took twelve percent of $600, you’ll get $72.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 16 hours after post)

Your right, I divided but then went a step further, I think I dropped a numder from another question there. Thank you for double checking! I would not have caught it.
Your assistance is more then appreciated. Be well, my friend, and my teacher said I was passing as of the last test, so I may be in the claer, I owe you. Shout out to me anytime you need anything, Ill try my best to get you a prompt response, yours..Gypsie

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (5 days, 16 hours after post)

Solve the system by substitution method.
x – y = –3
x – y = 4
I just need this last one, it does not have to be graphed, just solved. If you could show me how to set it up, I can work it

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Creal Default offline Verified User (6 years, 6 months) Long Term User Shouts: 1 #
Houston, TX, US | 5 years, 7 months ago (5 days, 23 hours after post)

Solve the system by substitution method.
x – y = –3
x – y = 4

Well, just by looking at this, I can tell you that these lines are going to be parallel and have no solution. If you add y to both sides:
x = y - 3
x = y + 4
And then add three to the first one and subtract four from the second:
x + 3 = y
x - 4 = y
You can see that these lines have the same slope but a different y-intersept. Therefore, this system has no solution.

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 7 months ago (6 days, 12 hours after post)

:) sorry, i see u already posted this one, thank you again for all your patience!

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gypsie offline Verified User (5 years, 8 months) Long Term User Shouts: 1 #
Rehoboth Beach, DE, US | 5 years, 4 months ago (3 months, 2 weeks after post)

Hey man thanx, Ive come a long way, Ive completed that course and moving onto my bachelors in psych, but I wunfortuanatly have to do another round of algebra, 2 to complete my degree, yuck..at least Ill have this site for assistnace. Im sure someone out there will be bord enuf to help..
anyways be well, and Ill be back round here if anyone needs me inbetween writing my reports and kids, and the new move to germany this summer, ..a lot of stress and excitement, Im ready to hit to go move already.
Everything except my numbers skills have improoved about 95%, Im driving, and exercising, and talking just fine. I can start running when the weather allos agaion, yahoo! Ill never give up, Ive defied death a couple times,, and think I have it in the strong hold for now..be well, J

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