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Math homework help?

if f(x) = 2x^2 + 4 and g(x) = x-3, which number satisfies h(x) = (f o g)(x) ?

a. 5
b. 2
c. 3
d. 4

i tried doing it and i got imaginary numbers and i don’t know what to do with them.
i got 3 + or - 4i square root of 2

This open post was written 9 months, 1 week ago | V/U/S: 124, 13, 4 | Edit Post | Leave a reply | Report Post


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Cole Becket offline Verified User (10 months, 2 weeks) Long Term User Shouts: 8 #
An Undisclosed Location | 9 months, 1 week ago (22 minutes after post)

What’s h(x)?

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Anonymous #
9 months, 1 week ago (27 minutes after post)

that’s what i asked myself. .__.

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Cole Becket offline Verified User (10 months, 2 weeks) Long Term User Shouts: 8 #
An Undisclosed Location | 9 months, 1 week ago (35 minutes after post)

there’s something missing I think

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Anonymous #
9 months, 1 week ago (42 minutes after post)

nope, straight out of my textbook.

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Cole Becket offline Verified User (10 months, 2 weeks) Long Term User Shouts: 8 #
An Undisclosed Location | 9 months, 1 week ago (47 minutes after post)
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Rico offline Verified User (9 months, 3 weeks) Long Term User Shouts: 4 #
US | 9 months, 1 week ago (6 hours, 53 minutes after post)

fog = 2(g(x))^2 + 4

plug the numbers into x in this case g(x)=x-3

ex
g(1)= 1-3 = -2

F(g(1)) = 2(-2)^2 + 4 = 12

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betta offline Verified User (1 year, 9 months) Long Term User Shouts: 2 #
Toronto, ON, CA | 9 months ago (1 week, 2 days after post)

so lets see here…

h(x)= f(g(x))
h(x)= 2(x-3)^2 + 4

the vertex of this function will be @ x = 3, h(x)=4

I agree there seems to be something missing. The reason being the text book should give you 2 numbers not 1. any number can be plugged into x, h(x) >= 4.

are you sure there weren’t more instructions above the problem in your text book?

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Rico offline Verified User (9 months, 3 weeks) Long Term User Shouts: 4 #
US | 9 months ago (1 week, 2 days after post)

I think its a case of not understanding the question betta. You might be on to something, like its asking for which numbers are not in the range. Yet he asked which numbers would work which is silly as all numbers work in the domain. How he got imaginary numbers is beyond me.

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betta offline Verified User (1 year, 9 months) Long Term User Shouts: 2 #
Toronto, ON, CA | 9 months ago (1 week, 2 days after post)

He could have gotten imaginary numbers by inverting the function so instead of it being y = f(x), it is x = f(y). That would provide a square root, and you put in a value in which the square root is of a negative number…

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Cole Becket offline Verified User (10 months, 2 weeks) Long Term User Shouts: 8 #
An Undisclosed Location | 9 months ago (1 week, 2 days after post)

Whatever the result, you could look at the problem different ways, but there has to be more instructions, but that was a week ago, I wonder what the “answer” was?

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betta offline Verified User (1 year, 9 months) Long Term User Shouts: 2 #
Toronto, ON, CA | 9 months ago (1 week, 2 days after post)

anon probably clarified with the math teacher. I bet it was a misreading of the text, or he/she didn’t post the full context of the question.

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Cole Becket offline Verified User (10 months, 2 weeks) Long Term User Shouts: 8 #
An Undisclosed Location | 9 months ago (1 week, 2 days after post)

THat happens too many times here, that’s why I sent him off to the other forum

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