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Math Help, Please and Thank You!

I have three Algebra II equations that I need help with.
I’ll be needing more help later, but this is a good start…

1) (x^10/3y^4)(9x^2y^2/x^4y^3)

2) (5x^3 - 2x^2 + 7) - (8x^2 - 11)

3) (x^3 - 10x^2 + 27x - 12) / (x - 4)

This open post was written 5 months, 4 weeks ago | V/U/S: 187, 7, 4 | Edit Post | Leave a reply | Report Post

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Since writing this post Moon may have helped people, but has not within the last 4 days. Moon is a verified member, has been around for 8 months, 1 week and has 18 posts and 149 replies to their name.

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alex39 offline Unverified User #
An Unknown Location | 5 months, 4 weeks ago (12 minutes after post)

just flunk and become a hobo

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Moon offline Verified User (8 months, 1 week) Long Term User Shouts: 16 #
Chico, CA, US | 5 months, 4 weeks ago (13 minutes after post)

Yes, why didn’t I think of that before? Lol. No thanks, I’ll save that as a last resort.

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Shoe-Lac offline Verified User (8 months, 1 week) Long Term User Shouts: 1 #
An Undisclosed Location | 5 months, 4 weeks ago (23 minutes after post)

Thats some other language to me.

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Moon offline Verified User (8 months, 1 week) Long Term User Shouts: 16 #
Chico, CA, US | 5 months, 4 weeks ago (24 minutes after post)

Well, do you know algebra 2 in general or is it just the way it’s typed that has you confused?

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tetrasydne offline Unverified User #
An Unknown Location | 5 months, 4 weeks ago (40 minutes after post)

Put it into Maple. It knows everything. I’m not sure what the order of operations on the first term is - is that 9((x^2)^y)^(2/x^4y^3)?

The second one is not that bad. Just subtract the coefficients of x^n - so for example, given polynomial (ax^2 + bx^3 + cx^4)-(dx^3 + ex^7 + fx^4 +yx^5) you get
ax^2 + (b-d)x^3 + (c-f)x^4 - yx^5 - ex^7.

You have to use long division on the last term. Basically, it’s the same as long division with integers. Ask what you would multiply the first term of (x-4) by (the first term is just “x”) to get the first term (x^3) of the second. Now since x*x^2 = x^3, you write x^2 at the top and multiply that through the rest of (x-4) - then subtract that from the (x^3 - 10x^2 + 27x - 12); you know, it’s the same as dividing numbers, where 3 can go into 13 4 times, so you write 4 at the top of the division symbol thing and subtract 4 from 13 to get a remainder. This is exactly the same, but you have to multiply things by x to get the thing inside. And once you reach the point where you’ve got nothing but constants left, you’re done and have a remainder. Kinda hard to explain on the internet. Look for a good math book at the library, maybe.

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