# Times help: The position of a racing car, which starts from rest at t = 0 and moves in a straight line. - Help.com

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## The position of a racing car, which starts from rest at t = 0 and moves in a straight line.

Estimate (a) its velocity and (b) its acceleration for the times and distances.
t(s) x(m) v(m/s) a(m/s2)
0.0 0.0
0.25 0.11
0.50 0.46
0.75 1.06
1.00 1.94
1.50 4.62
2.00 8.55
2.50 13.79
3.00 20.36
3.50 28.31
4.00 37.65
4.50 48.37
5.00 60.30
5.50 73.26
6.00 87.16

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### Replies (5)

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Acceleration is the rate of increase of speed. Put simply, velocity per time. So velocity / Time.

Divide each v value by t on each row to get a.

Help me with: Depression

For the first ex. t=.25 x=.11 and v=.44, therefore a should equal 1.76..correct? I am using an online program to turn in homework, and it is telling me this is the wrong answer…

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That’s right. Do you need to add units for the program to accept it? i.e. 1.76 m/s/s
Only thing I cna think of, because you got the Maths right, for the first example the acceleration should be 1.76. =)

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Thank you for the help

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No worries :)

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