Find help: an old wedding photograph which is rectangular has a diagonal length of 136 inches and height of 12inches find the width of the photograph. - Help.com

a^2+b^2=c^2

side a squared plus side b squared = c(hypotenuse)squared

or…

b squared = c squared - a squared

Cailean is right, you can use the pythagorean theorem: a^2 + b^2 = c^2
One way to think about it is to split the rectangle into two right triangles. The long diagonal length of 136 would be the hypotenuse (or c^2) and the height of 12 inches would be one of the sides (a^2 or b^2).
So you get 12^2 + b^2 = 136^2
144 + b^2 = 18496
Subtract 144 from both sides:
b^2 = 18352
Take the square root of both sides:
b ~= 135.469554
So the width would be 135.5 inches.

So, it would be an eleven foot wide wedding picture that’s one foot tall. Are you sure you didn’t leave out a decimal on the diagonal length or maybe one of the units isn’t in inches?

lol, that’s what I was thinking Creal

umm wouldnt those numbers not matter for the width? a triangle is 2d which is measured in length and height. width refers to a 3 dimensional object

but there are three sides to a triangle, even though it’s a two dimensional shape.
squares are 4 sided…etc

brain fart. first 3 answers are correct. it having 3 sides doesnt make it 3d it would be called a pyramid if it were 3d. was focusing on my pizza and not reading the question correctly

lol….triangular slices or squares?

hehe

im not a fan of brick style pizza, triangle styles of course

:-)