Thought help: I need help with this math problem. - Help.com

what does ^ mean?

to the power of

argh thats a tough one

Okay, add the like qualities, so it’s now:

6y+10x-5=0

you need to get it into standard form so you have to get the y alone. now it’s:

y=-10/6+5/6.

Now graph the y-intercept (it’s 5/6…the point that is on the y-line)

next graph the slope using your y-intercept.
So you go down 10 and then over 6.

Now draw a line between the two points.

Your line should be leaning left because the slope is negative.

Hope this helps
(:

y^2+x^2+4y+8x-5=0

Well, if you’re trying to graph this, it’s going to end up being a circle.
The form we’re looking for is (x - a)^2 + (y - b)^2 = r^2. So we can group the terms and complete the square:

y^2 + 4y + x^2 + 8x - 5
Let’s look at the y’s and x’s separately. We can find perfect squares:

(y + 2)^2 = y^2 + 4y + 4
(x + 4)^2 = x^2 + 8x + 16

So if we add 4 and 16 to both sides of the original equation, we can complete the square:
(y + 2)^2 + (x + 4)^2 - 5 = 4 + 16
(y + 2)^2 + (x + 4)^2 = 25

So looking back at the equation of the circle: (x - a)^2 + (y - b)^2 = r^2
We see that r^2 = 25, making r (the radius) = 5.
The center of the circle is located at the coordinates (a, b), so in this example the center would be at (-4, -2).

So in summary, the graph should be a circle with a radius of 5 centered at (-4,-2)

very neatly done. you’d think the original poster would know which unit they are on so they could start by themselves