algebra help: If one of two supplementary angles is 16 degrees smaller than three times the other, find the measure of the larger.

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If one of two supplementary angles is 16 degrees smaller than three times the other, find the measure of the larger.

D: how would i set this problem up?
I get that you would put 3n-16 somewhere in the equation, but would come before the 3n-16?

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junz8 #
An Unknown Location | 10 months, 3 weeks ago (7 minutes after post)

supplementary angles add up to 180
should be
x+3x-16=180
where 3x-16 is the larger

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Mr. P 2 #
An Undisclosed Location | 10 months, 3 weeks ago (8 minutes after post)

Supplements total 180 degrees. With one angle being x, we plug in 3x-16 for the second and form the equation:

180 = x + (3x - 16)

180 = 4x - 16

196 = 4x

49 = x

So one angle is 49, and plugging back in:

3(49) - 16 =

131

Since 131 > 49,

The larger is 131 degrees.

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