math help: How do I solve for the x in this equation? - Help.com

bluesilver8
offline Verified (3 months, 1 week) Visit bluesilver8's shoutbox
An Unknown Location

How do I solve for the x in this equation?

e^(5x + 4) = 7e^(4 - x)

I can’t figure it out for the life of me… but looking at it makes me think the method of getting the solution is fairly easy. Can someone help me out?

This closed post was written 3 months ago | V/U/S: 116, 4, 3 | Edit Post | Report Post


Reciprocity (0) Reciprocation Failure -- The poster has NOT helped anyone else yet!

Since writing this post bluesilver8 may have helped people, but has not within the last 4 days. bluesilver8 is a verified member, has been around for 3 months, 1 week and has 6 posts and 2 replies to their name.

Post Tags (3)

Calculus, math, E (How Tags Affect Reciprocity)

Replies (4)

Where were you?

Click and drag to move the map around. FAQ: How we place people on this map »
You can also watch events on Help.com as they happen
Mouse over the map for 2 seconds to see an expanded, interactive view

Arkia Valkair offline Verified User (7 months, 3 weeks) Long Term User Shouts: 26 #
An Unknown Location | 3 months ago (11 minutes after post)

Well, the first step is to take the natural logarithm (ln) of both sides. This will get you…

5x + 4 = 4 - x + ln(7)

You should be able to figure it out from there. If you want you can find ln(7) on most calculators, but I suggest just leaving it as ln(7).

Quote this reply Report this reply to moderators
gilraf offline Verified User (2 years, 4 months) Long Term User Shouts: 0 #
Bronx, NY, US | 3 months ago (20 minutes after post)

5x+4 = 4-x You need to make one side of the equation equal zero.
+x-4 So You Move everything to one side.
__________
6x=0 Solve for x.
x=0/6 or simply 0
___________

This is the actual answer sorry about the previous one.

Quote this reply Report this reply to moderators
Help me with: I’m sick and tired of being single…I would like for at least to have a female friend to go out with ….People

bluesilver8 closed this post.

This post has been closed, no more replies. Thanks!

Invite Others to Help

Seeing as this post is closed, no invites are allowed.