change help: 2 H2(g) + O2(g) 2 H2O(l) ΔH = +571.6 kJ

sarahbriggs2

2 H2(g) + O2(g) 2 H2O(l) ΔH = +571.6 kJ

Refer to the chemical equation above. What is the approximate enthalpy change for the formation of 1.90 mol of water? Include the sign in your answer.

This open post was written 1 year, 5 months ago | V/U/S: 936, 3, 4 | Edit Post | Leave a reply | Report Post

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Since writing this post sarahbriggs2 may have helped people, but has not within the last 4 days. sarahbriggs2 is a verified member, has been around for 5 years, 4 months and has 10 posts and 12 replies to their name.

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Chemical equation, Formation, Enthalpy, Equation, Answer, change, Refer, Water, Sign, mol (How Tags Affect Reciprocity)

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ProffVampy 18 #
An Unknown Location | 1 year, 5 months ago (25 minutes after post)

NOOOEs…sorry doing this in chem at the moment….blek

you not given any other data?

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Luck of the Irish 4 #
An Undisclosed Location | 1 year, 5 months ago (41 minutes after post)

http://answers.yahoo.com/question/ind…

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irregularone 2 #
An Unknown Location | 1 year, 5 months ago (42 minutes after post)

if no other data is given im guessing probably 571.6 x 1.90. But tahts with exess O2 and H20. did you forget to put a -> to h20 btw?

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change help: 2 H2(g) + O2(g) 2 H2O(l) ΔH = +571.6 kJ - Help.com

2 H2(g) + O2(g) 2 H2O(l) ΔH = +571.6 kJ

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