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Help solve this boolean expression (Answer given) !

A.B.C+A.B’.C’+A’.C’+A’.B.D’+B.C’

(solution: BA+BD+C’)

Can’t get around it using any identity!

This open post was written 1 year, 2 months ago | V/U/S: 424, 3, 4 | Edit Post | Leave a reply | Report Post


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Since writing this post dohrem may have helped people, but has not within the last 4 days. dohrem is not a verified member, has been around for 1 year, 2 months and has 1 posts and 0 replies to their name.

Post Tags (9)

Boolean expression, Expression, identity, Solution, boolean, Answer, electrical, engineering, algebra (How Tags Affect Reciprocity)

Replies (3)

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Dr. Jackson offline Verified User (5 years, 1 month) Long Term User Shouts: 43 #
An Unknown Location | 1 year, 2 months ago (1 hour, 14 minutes after post)

mintra wrote:
yABa daBA doo

Roflmao

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Help me with: Making a profit off of currency exchange rates.
desertgalleon offline Verified User (2 years, 2 months) Long Term User Shouts: 1 #
An Undisclosed Location | 1 year, 2 months ago (5 hours, 25 minutes after post)

Dohrem wrote:
A.B.C+A.B’.C’+A’.C’+A’.B.D’+B.C’

(solution: BA+BD+C’)

Nope, as you have written it, those are not equivalent. E.g.: (A=0, B=1, C=1, D=0) yields TRUE for the first expression, from your 4th OR’d term, but yields false in your incorrect simplification.

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