# Answer help: Help solve this boolean expression (Answer given) ! - Help.com

## Help solve this boolean expression (Answer given) !

A.B.C+A.B’.C’+A’.C’+A’.B.D’+B.C’

(solution: BA+BD+C’)

Can’t get around it using any identity!

This open post was written 1 year, 2 months ago | V/U/S: 424, 3, 4 | Edit Post | Leave a reply | Report Post

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### Replies (3)

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yABa daBA doo

mintra wrote:
yABa daBA doo

Roflmao

Dohrem wrote:
A.B.C+A.B’.C’+A’.C’+A’.B.D’+B.C’

(solution: BA+BD+C’)

Nope, as you have written it, those are not equivalent. E.g.: (A=0, B=1, C=1, D=0) yields TRUE for the first expression, from your 4th OR’d term, but yields false in your incorrect simplification.

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